# Which Statement Best Describes The Polarity Of CH3Cl? A) The Molecule Is Always Polar. B) The Molecule (2023)

Chemistry High School

a) The molecule is always polar.

Explanation:

The molecule is always polar because of two reasons:

• all the bonds are polar due to the difference in electronegativity between carbon and hydrogen & carbon and chlorine.

AND IMPORTANTLY

• The molecule is asymmetrical meaning that the dipoles cannot cancel each other out (like they do in methane or carbon dioxide for example) so the net effect is a polar molecule.

## Related Questions

Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other has carbon tetrachloride as the solvent. Determine that molal concentration, m (or b), and boiling point, Tb. benzene boiling point=80.1 Kb=2.53

carbon tetrachloride boiling point=76.8 Kb=5.03

Molal concentration,

Boiling point,

Boiling-point elevation:

It describes the phenomenon that the boiling point of a liquid (a solvent) will be higher when another compound is added, meaning that a solution has a higher boiling point than a pure solvent.

The formula for boiling point elevation is:

............(a)

i) For benzene

............(1)

ii) For carbon tetrachloride

............(2)

On equating equations 1 and 2:

Thus, value of molal concentration is 1.32m.

Now, substituting value for m in equation a:

brainly.com/question/4206205

Concentration = 1.32 m

Boiling point =

Explanation:

Let the boiling point of two solutions = T

Let the molal concentration of the two solutions= m

The relation between elevation in boiling point and molal concentration is:

i) For benzene

....(1)

ii) For carbon tetrachloride

...(2)

Equating the two equations:

Putting value of "m" in equation "1"

Which of the following statements is true about the following reaction? 3NaHCO3 (aq) + C6H8O7 (aq) + 3CO2 (g) + 3H2O (s) + Na3C6H5O7 (aq)

a) 22.4 L of CO2(g) are produced for every liter of C6H8O7(aq) reacted.
b) 1 mole of water is produced for every mole of carbon dioxide produced.
c) 6.02 X 10^23 molecules of Na3C6H5O7(aq) are produced for every mole of NaHCO3(aq) used.
d) 54g of water are produced for every mole of NaHCO3(aq) produced

The correct reaction equation is:

b) 1 mole of water is produced for every mole of carbon dioxide produced.

Explanation: CONVERT EVERYTHING TO MOLES OR VOLUME, THEN COMPARE IT WITH THE COMPOUND'S STOICHIOMETRY IN CHEMICAL EQUATION.

a) 22.4 L of gas is produced only when L of is reacted with 22.4 L of . So it is wrong.

b) Since in the chemical equation the stoichiometric coefficient of and are same so the number of moles or volume of each of them will be same whatever the amount of reactants taken. Therefore it is correct option.

c) molecules is equal 1 mole of if produced then 3 moles of is required, which is not given in the option. So it is wrong.

d) 54 g of water or 3 moles of (Molecular Weight of water is 18 g) is produced when 3 moles of is used but in this option only one mole of is given. So it is wrong.

Connexus: A,A,A,B.

Explanation:

These are the correct answers to Chemical Calculations Lesson 2 unit 6 stoichiometry answers.

Hope this helps:)

What is the unknown metal if the temperature of a beaker of 100ml of water was raised 17c to 19 c when 21 grams of the metal at 122.5c was placed into the beaker ?

The metal has a heat capacity of 0.385 J/g°C

This metal is copper.

Explanation:

Step 1: Data given

Mass of the metal = 21 grams

Volume of water = 100 mL

⇒ mass of water = density * volume = 1g/mL * 100 mL = 100 grams

Initial temperature of metal = 122.5 °C

Initial temperature of water = 17°C

Final temperature of water and the metal = 19 °C

Heat capacity of water = 4.184 J/g°C

Step 2: Calculate the specific heat capacity

Heat lost by the metal = heat won by water

Qmetal = -Qwater

Q = m*c*ΔT

m(metal) * c(metal) * ΔT(metal) = - m(water) * c(water) * ΔT(water)

21 grams * c(metal) *(19-122.5) = -100 * 4.184 * (19-17)

-2173.5 *c(metal) = -836.8

c(metal) = 0.385 J/g°C

The metal has a heat capacity of 0.385 J/g°C

This metal is copper.

Select all that apply. Which statements correspond to cellular respiration? O 2 is pumped in and forces CO 2 out. CO 2 diffuses passively out of the cell. CO 2 must be pumped out of the cell. CO 2 diffuses passively into the cell. O 2 diffuses passively when converted to CO 2. O 2 diffuses passively when produced inside the cell.

The correct answer is CO2 diffuses passively out of the cell.

Explanation:

Carbon dioxide is one of the end product of cellular metabolism.CO2 is produced as waste material inside the body after cellular respiration.

Carbon dioxide is transported out from the body by passive diffusion process which helps the CO2 gas to move along the concentration gradient from high concentration region(body) to the low concentration region(atmosphere).

Thus CO2 ia being eliminated from our body.

Oxygen gas, generated by the reaction 2KClO3(s)---2KCl(s)+3O2(g), is collected over water at 27•C in 3.72L vassel at a total pressure of 730 torr.(The vapor pressure of H2O at 27•C is 26.0 torr). How many moles of KClO3 were consumed in the reaction? Oxygen gas, generated by the reaction 2KClO3(s)---2KCl(s)+3O2(g), is collected over water at 27•C in a 1.16L vessel at a total pressure of 1.00 atm ( The vapor pressure of H2O at 27•C is 26.0 torr) How many moles of KClO3 were consumed in the reaction?

moles = 0.093 moles

Explanation:

In this case, we know that this reaction is taking plave in a vessel that has a 730 torr of total pressure.

The total pressure is a value obtained by:

Pt = Pwater + PO2

We need to know the pressure of O2, because then, with stoichiometry, we can calculate the moles of KClO3

The pressure of oxygen is:

PO2 = 730 - 26 = 704 Torr

Now, this pressure is in Torr, and we need to convert it to Atm, so:

704 Torr / 760 Torr = 0.9263 atm

Now, let's use the ideal gas equation:

PV = nRT

With this expression, we will calculate the moles of O2, and then, the moles of KClO3:

n = PV/RT

R = 0.082 L atm /K mol

P = 0.9263 atm

V = 3.72 L

T = 27 + 273 = 300 K

Replacing the data:

n = 0.9263 * 3.72 / 300 * 0.082

n = 0.14 mole

Finally, by stoichiometry, we know that 2 moles of KClO3 produces 3 moles of O2, so:

moles of KClO3 = 0.14 * 2/3 = 0.093 moles of KClO3

When a 0.80 g sample of unknown Fe2+ salt is titrated with 0.0285 M K2Cr2O7. it is found that 59.2 mL of this dichromate solution are required to reach the equivalence endpoint b. calculate the percent iron in the unknown using the balanced equation

Answer: The percent of iron (II) ions in the sample is 71.25 %

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of dichromate solution = 0.0285 M

Volume of solution = 59.2 mL = 0.0592 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

The chemical equation for the reaction of iron (II) ions with potassium dichromate follows:

By Stoichiometry of the reaction:

1 mole of dichromate solution reacts with 6 moles of iron (II) ions

So, 0.0017 moles of dichromte solution will react with = of iron (II) ions

• To calculate the mass of iron (II) ions for given number of moles, we use the equation:

Molar mass of iron = 55.85 g/mol

Moles of iron = 0.0102 moles

Putting values in above equation, we get:

• To calculate the mass percentage of iron (II) ions in sample, we use the equation:

Mass of sample = 0.80 g

Mass of iron (II) ions = 0.570 g

Putting values in above equation, we get:

Hence, the percent of iron (II) ions in the sample is 71.25 %

Consider the reaction . How much NH₃ can be produced from the reaction of 74.2 g of N₂ and 14.0 moles of H₂? a. 1. 1.59 × 10²⁴ molecules b. 2. 1.69 × 10²⁵ molecules c. 3. 3.19 × 10²⁴ molecules d. 4. 1.26 × 10²⁵ molecules e. 5. 5.62 × 10²⁴ molecules

How much NH₃ can be produced from the reaction below:

N₂ + 3H₂ - 2NH₃

The stoichiometric ratio of the reactants = 1:3

Given

74.2g of N₂, and Molar mass = 14g/mole

Mole of N₂ = 74.2/14=5.3mols of N₂,

and 14mols of H₂

From this given values and comparing with the stoichiometric ratio, H₂ will be the limiting reagent while N₂ is the excess reactant.

i.e, for every 14mols of H₂, we need 4.67mols of N₂ to react with it to produce 9.33mols of NH₃ as shown (vice versa)

From this we have 9.33mols of NH₃ produced

Avogadro constant, we have n = no of particles = 6.022x10²³ molecules contained in every mole of an element.

For a 9.33mols of NH3, we have 9.33x6.022x10²³molecules in NH3

5.62x10²⁴molecules of NH₃

During the formation of an ionic compound, the element with the higher ionization energy will gain electrons. True or False

False because you have to take it out and do it right

Which of the following statements are true?Check all that apply.a. There are gas molecules that move faster than the average.b. The average speed of gas molecules increases with temperaturec. All the gas molecules in a sample have the same Kinetic energyd. There are gas molecules that move slower than the average.e. The average Kinetic energy of gas molecules increases with temperature.

Options a, b, d and e are correct.

Explanation

Options a) and d) are correct because that's what an average speed means. Gas molecules have different speeds, and what we can easily measure is the average speed of all of them, this would logically mean that there are some molecules that move at a higher/lower speed than the average.

Option e) is correct because the average kinetic energy K is dependant on the temperature T as seen by the formula K=1.5*R*T. This would also mean that option b) is correct because a higher kinetic energy means there is a higher speed.

A 5.00 mL of a salt solution of unknown concentration was mixed with 35.0 mL of 0.523 M AgNO3. The mass of AgCl solid formed was 0.508 g. _AgNO3 (aq) +_NaCl (aq)AgC1(s) _NaNOs (aq) What is the chemical term for the silver chloride solid that is formed? Select one: O A. Bubbles B. Barnacles C. Precipitate D. Solubles E. None of these terms

The silver chloride solid that is formed, is a Precipitate (Option C)

Explanation:

AgNO3 (aq) + NaCl(aq) → AgCl(s) ↓ + NaNO4 (aq)

AgNO3 (aq) → Ag⁺(aq) + NO3⁻(aq)

NaCl(aq) → Cl−(aq) + Na+(aq)

Ag⁺(aq) + Cl⁻(aq) → AgCl (s)↓

In the presence of chlorides, the silver cation binds to the anion through an ionic bond to generate the salt, which is an insoluble solute

Discuss how the following factors determine the rate of electron transfer in biological systems: (a) the distance between electron donor and acceptor, and
(b) the reorganization energy of redox active species and the surrounding medium.

Explanation:

(a). HOW THE DISTANCE BETWEEN ELECTRON DONOR AND ACCEPTOR AFFECTS THE RATE OF ELECTRON TRANSFER IN BIOLOGICAL SYSTEM:

Distance between the acceptor and the donor can affect in two ways; short distance and long distance effect.

Short distance causes

electronic orbitals of donor and acceptor directly overlap whereas in LONG DISTANCE reactions this coupling is indirect because of

sequential overlaps of atomic orbitals of the donor, the intervening medium, and the orbitals of the acceptor.

(b). HOW REORGANIZATION ENERGY OF REDOX ACTIVE SPECIE SURROUNDING MEDIUM AFFECTS:

the reorganized energy does not depend on the pre-existing intra molecule electric field. The charge transferred inside the molecule interacts with its aqueous surroundings.

Reorganized energy can be calculated using Poisson-Boltzmann equation.

Ionic compounds generally have lower boiling and melting points than covalent compounds. True or False

The given statement is false.

Explanation:

Ionic bond is formed by strong electrostatic attraction between two atoms having large difference in their electronegativity.This strong electrostatic attraction provide structural stability to the ionic compounds.For example NaCl.

The ionic compounds generally are solid in nature.As a result their melting point and boiling point are higher that covalent compounds as covalent compounds exist in liquid of gaseous state.

The acid dissociation constant Ka equals 1.26 × 10–2 for HSO4– and is 5.6 × 10–10 for NH4. Which statement about the following equilibrium is correct? HSO4–(aq) + NH3(aq) SO42–(aq) + NH4+(aq)

The reaction will favour the reactants because ammonia is a stronger base compare to the sulphate ion.

When is a covalent bond described as polar? Choose one: when electrons are transferred from one atom to another if covalently bonded atoms are electrically charged if electrons are shared unequally between bonded atoms when the bonded atoms are of dif

if electrons are shared unequally between bonded atoms

Explanation:

A polar covalent bond is a bond that is formed due to the unequal distribution of electrons between two partially charged atoms. This is observed when the difference in electronegativity between the bond atoms is between 0.5 and 1.7.

A polar bond is a covalent bond between two atoms where the electrons that form the bond are unevenly distributed. This causes the molecule to have a slight electric dipole moment where one end is slightly positive and the other is slightly negative.

The charge of the electric dipoles is less than a full unit charge, so they are considered partial charges and are called delta plus (δ +) and delta minus (δ-).

Because positive and negative charges are separated at the bond, molecules with polar covalent bonds interact with the dipoles of other molecules. This produces intermolecular dipole-dipole forces between the molecules.

A mixture of 1.374g of H2 and 70.31g of Br2 is heated in a 2.00 L vessel at 700 K. These substances react as follows: H2(g) + Br2(g) <---> 2HBr(g) At equilibrium the vessel is found to contain 0.566g of H2.
a. Calculate the equilibrium concentrations of H2, Br2 and HBr.
b. Calculate Kc.

a. 0.139 M → [H₂] ; 0.217 M → [Br₂] ; 0.01 M → [HBr]

b. Kc = 3.31x10⁻³

Explanation:

H2(g) + Br2(g) ⇄ 2HBr(g)

Initial 1.374 g 70.31 g -

reacts X X 2x

eq. (1.374 - x) (70.31-x) 2x

In equilibrium I see, the grams I initially had minus some mass which has reacted. In products I have the double of that mass, because the stoichiometry.

So I have the mass in equilibrium, of H2 and of course I can know the mass which has reacted.

1.374g - x = 0.556 g

1.374g - 0.556 g = x = 0.808 g (This is the mass which has reacted)

70.31g - 0.808 g = 69.502 g (Mass in equilibrium of Br2)

2 . 0.808 g = 1.616 g (Mass in equibrium of HBr)

By molar mass, we can kwow the moles.

Molar mass H2: 2 g/m

Moles = mass / molar mass → 0.556 g / 2 g/m = 0.278 moles

Molar mass Br2: 159.80 g/m

Moles = mass / molar mass → 69.502 g / 159.80 g/m = 0.434 moles

Molar mass HBr: 80.9 g/m

Moles = mass / molar mass → 1.616 g / 80.9 g/m = 0.02 moles

The moles are not molarity. In equilibrium, to calculate Kc we need molarity (moles/L). The moles we have calculated are in 2 L of mixture so:

moles / L = molarity

0.278 moles / 2L = 0.139 M → [H₂]

0.434 moles / 2L = 0.217 M → [Br₂]

0.02 moles / 2L = 0.01 M → [HBr]

Kc = [HBr]² / ([H₂] . [Br₂])

Kc = 0.01² / (0.139 . 0.217) = 3.31x10⁻³

Give the IUPAC name for the following structure: 3-chloro-6-methylcyclohexanol 2-methyl-5-chlorocyclohexanol 1-chloro-4-methylcyclohexanol 5-chloro-2-methylcyclohexanol 2-methyl-3-chlorocyclohexanol

5-chloro-2-methylcyclohexanol

Explanation:

There is no structure for the compound, but we can analyze the proposed options using the IUPAC rules to name organic compounds.

IUPAC rules state that to name an organic compound, first we have to identify the priorities for the functional groups present in the compound. In this case, the priority functional group is the alcohol group, so we will start the counting of the carbons in this group. Then, the counting of carbon atoms is followed by the next substituents so they have the lowest possible numbers, in this case, we can assign the number 2 to the methyl group and 5 to the chloride group, and name the compound in alphabetical order, using commas to separate the words from the numbers and with no space between the words.

Since the other options involve: high countings for the susbtituents groups (3-chloro-6-methylcyclohexanol), wrong assignation of priority functional group (1-chloro-4-methylcyclohexanol), wrong sequence of counting in the compound (2-methyl-3-chlorocyclohexanol) and no alphabetical order to name the compound (2-methyl-5-chlorocyclohexanol), the correct option is:

5-chloro-2-methylcyclohexanol

Have a nice day!

Classify the following bonds as ionic, polar covalent, or covalent, and give your reasons: (a) the CC bond in H3CCH3, (b) the KI bond in KI, (c) the NB bond in H3NBCl3, (d) the CF bond in CF4.

Answer: a) the C-C bond in : covalent

b) the KI bond in KI : ionic

c) NB bond in : polar covalent

d) the CF bond in : polar covalent

Explanation:

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

A polar covalent bond is defined as the bond which is formed when there is a difference of electronegativities between the atoms.

An ionic bond is formed when an element completely transfers its valence electron to another element. This bond is formed between a metal and an non-metal.

a) the C-C bond in : covalent as there is no diffrence in electronegativity

b) the KI bond in KI : ionic as potassium transfers electron to iodine.

c) NB bond in : polar covalent as there is difference in electronegativity

d) the CF bond in : polar covalent as there is difference in electronegativity

Which element has the lowest ionization energy?

A. By
B.Al
C. Cl

Sodium

Explanation:

Sodium will have lowest ionization energy because the given three elements are present in same period. As we move from left to right ionization energy increased so chlorine will have highest ionization energy.

Ionization energy trend along period:

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Given the lattice energy of NaCl = 787 kJ/mol, the ionization energy of Na = 496 kJ/mol and the electron affinity of Cl = −349 kJ/mol, calculate the ΔH o for the reaction: Na(g) + Cl(g) → NaCl(s)

Answer : The value of for the reaction is, -640 KJ/mole

Explanation :

The steps involved in the formation of :

(1) Conversion of gaseous sodium atoms into gaseous sodium ions.

= ionization energy of sodium = 496 kJ/mol

(2) Conversion of gaseous chlorine atoms into gaseous chlorine ions.

= electron affinity energy of chlorine = -349 kJ/mol

(3) Conversion of gaseous cations and gaseous anion into solid sodium chloride.

= lattice energy of sodium chloride (always negative) = -787 kJ/mol

To calculate the overall energy the equation used will be:

Now put all the given values in this equation, we get:

Therefore, the value of for the reaction is, -640 KJ/mole

The solid rocket boosters for the space shuttle employ a mixture of aluminum and ammonium perchlorate (molar mass = 117 g/mol) as fuel. The balanced equation is 3Al(s) + 3NH4ClO4(s) Al2O3(s) + AlCl3(s) + 3NO(g) + 6H2O(g). How many liters of gas measured at STP are produced from 235 g of NH4ClO4 with excess aluminum?

Answer : The volume of gas at STP produced are 45.0 L

Explanation :

First we have to calculate the moles of ammonium perchlorate.

Molar mass of = 117 g/mole

Now we have to calculate the moles of gas produced during the reaction.

The balanced chemical reaction is,

From the reaction we conclude that,

As, 3 moles of produces 3 moles of NO gas

So, 2.01 moles of produces 2.01 moles of NO gas

Now we have to calculate the volume of gas at STP.

At STP, 1 mole of substance occupy 22.4 L volume of gas.

As, 1 mole of NO gas occupy 22.4 L volume of gas.

So, 2.01 mole of NO gas occupy 2.01 × 22.4 L = 45.0 L volume of gas.

Therefore, the volume of gas at STP produced are 45.0 L

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